How many moles of NO₂ would be required to produce 4.85 moles of HNO₃ in the presence of excess water in the following chemical reaction? 3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

Answer 1

The balanced equation shows that 3 moles of NO2 are required to produce 2 moles of HNO3. The conversion ratio to use is 3 mNO2/2 mHNO3 and the calculation is

3 mNO2/2 mHNO3 x 4.85 mHNO3 = 7.28 moles NO2 required.