A common first line of thought would be that in order to double the height (increase it by 100%), you would have to enlarge it by 20% 5 times.
However, thinking more accurately, you are not adding 20% of the original height with each iteration. Instead, you are adding 20% of the height that is now there, which means it should take fewer than 5 enlargements.
To calculate how many, we recognize that each enlargement multiplies the existing height by 1.2. This will result in exponential growth. To set up the equation, reason like this: 3.5" is the original height, and to multiply repeatedly by 1.2, we use exponentiation to raise 1.2 to the power we need:
n: # of 20% enlargements h(n): height of the image after n enlargements
h(n) = 3.5·1.2n , for n = 0, 1, 2, 3, etc. Finally, set h(n) = 7 and solve. This would require logs, and would result in an exact answer that was not a whole number, so instead we just need to find the first positive integer power of 1.2 that exceeds 2: 1.21 =1.2 , 1.22 = 1.44 , 1.233 = 1.728 , 1.244 = 2.0736.
So our answer is 4.