Use the chart to determine which type of bond is formed between potassium (K) and chlorine (Cl).

Question

Elements	Electronegativity
aluminum (Al)	1.61
calcium (Ca)	1
carbon (C)	2.55
chlorine (Cl)	3.16
fluorine (F)	4
hydrogen (H)	2.2
iron (Fe)	1.83
nitrogen (N)	3.04
oxygen (O)	3.44
phosphorus (P)	2.19
potassium (K)	0.82
silicon (Si)	1.9
sulfur (S)	2.58

A. 

nonpolar covalent

B. 

moderately polar covalent

C. 

highly polar covalent

D. 

ionic

Answer 1

If the electronegativity difference is greater than 1.7, the bond is ionic. Subtract the electronegativity of potassium from that of chlorine (3.16 - 0.82) to get 2.34 so, definitely ionic.