Average Value = [f(b) - f(a)]/(b - a) = [f(5) - f(0)]/(5 - 0) = [-25e^(-5/2)]/5 = -5e^(-5/2)
Muhammad C.
tutor
This should be correct unless you are doing the Mean Value Theorem in which there is a value between the interval for the derivative of the function so that it equals the average value of the function aka:
f'(c) = [f(b) - f(a)]/(b - a)
Report
02/28/15
Dalia S.
im not sure what you mean?
Report
03/01/15
Muhammad C.
tutor
I'm sorry for the confusion. It seems like I did it wrong to begin with.
Average value = [f(5) - f(0)]/(5 - 0) = (-25e^-25)/5 = -5e^-25
Report
03/01/15
Dalia S.
02/28/15