How many moles of NO can be produced from 0.680 g of NH 3 according to the following reaction? 4 NH 3 + 5 O 2 → 4 NO + 6 H 2 O

Answer 1

Since the equation is balanced, we see that 4 moles of NH₃ is needed to create 4 moles of NO, thus a 1:1 ratio.

1 mole of NH₃ has mass 14+3 =17 g thus 0.680 g of NH₃ = 0.068/17 = 0.04 moles of NH₃

Thus from the reaction 0.04 moles of NO is produced