determine the C* temp of 2.49 mol of a gas contained in a 1.00L vessel at the pressure of 1.39atm

Question

R=0.0821 L*atm/mol*K and K=*C +273

Answer 1

Hi Abigail! Here's the work:

(Pressure) (Volume) = (Number of moles) (gas constant R) (Temperature)

PV = nRT

(1.39atm) (1.00L) = (2.49 mol) (0.0821 L*atm/mol*K) (T)

1.39 = 0.204 (T)

T = 6.81 K

6.81K = *C + 273

Temperature *C = -266

Hope this helps! Feel free to reach out if you have any additional questions or help needed.