chemistry hw ideal gas help

Question

using the modified gas law (PM=dRT), calculate the value of density of the gas if the pressure is 250KPa and temperature is 255K. (The molar mass (M) of the gas is 4g/L and the value of R is 8.314 L.KPa/mol.K). Extension: use the periodic table to identify the gas

Answer 1

PM=dRT

P=250KPa

T=255k

M=4g/L

d=8.314

(250kpa)(4g/L) = (d) ( 8.314 L.KPa/mol.K)(255k)

-------------------------- _____________________

8.314 L.KPa/mol.K)(255k) 8.314 L.KPa/mol.K)(255k)

(250)(4g)

__________ = (d) all the units disappear except

(8.314 L)(255)

(d) = (0.471 g/L)