moles of 109.3 g phenol = 109.3 g P ( 1mole P/99.4 g P)
Do the same for acetone.
xP = nP/(nP + nA) where x is mole fraction and n is moles. Good luck!
Moh D.
asked • 02/06/21A solution is made using 103.9 g of phenol (MM = 94.11 g/mol) and 70.0 g of acetone (MM = 58.08 g/mol). What is the mole fraction of the phenol in the solution?
A solution is made using 103.9 g of phenol (MM = 94.11 g/mol) and 70.0 g of acetone (MM = 58.08 g/mol). What is the mole fraction of the phenol in the solution?
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