hat is the molality of lithium ions in a 0.302 m solution of Li₃PO₄ assuming the compound dissociates completely?

Question

hat

is

the

molality

of

lithium

ions

in

a

0.302

m

solution

of

Li₃PO₄

assuming

the

compound

dissociates

completely?

Answer 1

molality of solution = moles of solute / kg of solvent

Li3PO4 is lithium phosphate, an ionic compound from lithium ion and phosphate ion

lithium ion = Li+

phosphate ion = PO43-

Since the question ask for only molality of lithium ions, let me answer the question for the molality of phosphate ion and you can use it as guidance.

(1) There is one mole of phosphate ion in one mole of lithium phosphate.

(2) Given 0.302 m solution of lithium phosphate and with a 1:1 ratio of phosphate ion to lithium phosphate, there are 0.302 m of phosphate ion.

How many mole of lithium ion in one mole of lithium phosphate?

What is the ratio of lithium ion to lithium phosphate?

If you need to know the total molality of ions, then it'll be the sum of the molalities of lithium ion and phosphate ion.