A school is constructing a rectangular play area against an exterior wall of the school building. It uses 120 feet of fencing material to enclose three sides of the play area.

Question

It goes to three questions

Answer 1

120 = L+2W

LW =area.

to maximize area with given fencing that would make Width = 30 feet and length = 60

A= LW = (120-2W)W = 120W -2W^2

A' = 120-4W =0

W = 30

L=120-2(30) = 60 feet

W by L is 30 by 60 feet for max area