What quantity of energy in joules is required to cool a sample of mercury that weighs 56.9 g from 46 ºC to 25 ºC?

Answer 1

The formula necessary is m * c * ∆T = Energy; where m = mass, c = specific heat, ∆T is the change in Temperature.

Looking up the specific heat of mercury, c = 0.14

m = 56.9 g; ∆T = Final temperature - Initial temperature = 25°C - 46 °C = -21; c = 0.14

m*c*∆T = 56.9 g * -21 °C * 0.14 J/(g*°C) = -167 J or 167 J released