
Yefim S. answered 02/02/21
Math Tutor with Experience
Let we have exponential model A = A0ert.
(a) In 31.7 years A = A0/2. So, A0/2 = A0e31.7r ; r = ln(1/2)/31.7 = - 0.021866
A = A0e- 0.021866t is our model.
(b) 300 = 400e- 0.021866t; t = ln(3/4)/(- 0.021) = 13.2 years
(c) A = 400e- 0.021866·20 = 258.306 g