
Mark M. answered 02/03/21
Mathematics Teacher - NCLB Highly Qualified
0.32 = e-0.00012t
ln 0.32 = -0.00012t
-1.139 ≈ -0.00012t
9495.29 ≈ t
Jessica R.
asked 02/02/21The amount of carbon 14 present in a paint after t years is given by A(t)=A0 e-0.00012t. The paint contains 32% of its carbon 14. Estimate the age of the paint. Round to the nearest year as needed.
Mark M. answered 02/03/21
Mathematics Teacher - NCLB Highly Qualified
0.32 = e-0.00012t
ln 0.32 = -0.00012t
-1.139 ≈ -0.00012t
9495.29 ≈ t
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