
Yefim S. answered 02/02/21
Math Tutor with Experience
A(t) = 0.26A0; so, 0.26A0e-0.00012t; ln(0.26) = - 0.00012; t = ln(0.26)/(-0.00012) = 11225.6 years
Jessica R.
asked 02/02/21The amount of carbon-14 present in animal bones after t years is given by A(t)=A0e-0.00012t. A sample of fossil had 26% of the carbon 14 of a contemporary living sample. Estimate the age of the sample. Round to the nearest year as needed.
Yefim S. answered 02/02/21
Math Tutor with Experience
A(t) = 0.26A0; so, 0.26A0e-0.00012t; ln(0.26) = - 0.00012; t = ln(0.26)/(-0.00012) = 11225.6 years
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