please help me please i have been stuck for many hours

Question

Question 1: 3 Cu  +   8HNO₃   g 3 Cu(NO₃)₂   +  2 NO  +  4  H₂O

In the above equation how many moles of NO can be made when 60 moles of HNO₃ are consumed?



Question 2: 2 NH₃  +  3 CuO   g  3 Cu  +  N₂  +   3 H₂O

In the above equation how many moles of water can be made when 79 moles of NH₃ are consumed?

Question 3: S   +   6 HNO₃  -->  H₂SO₄  +  6 NO₂  +   2 H₂O

In the above equation how many moles of water can be made when 47 moles of HNO₃ are consumed?

Please give and only give explanation and solution please.

Answer 1

Alright. Looks like you've balanced the equations or they were already balanced.

Remember to check that aspects first and foremost.

Put an index finger on NO and another on HNO3.

It reads "for every 2 NO, you'll need 8 HNO3" or "for every 8 HNO3, you'll need 2 NO".

With moles it becomes "for every 2 moles of NO, you'll need 8 moles of HNO3" or "for every 8 moles of HNO3, you'll need 2 moles of NO"

NOTE: These relationships/ratios do not work with grams ..... If given grams, you'll need to convert to moles.

Now, for example .....If I was given 10 moles of NO, that's 5 times more than the 2 moles in the equation.

So, I'll need 5 times more of the HNO3. 40 moles of HNO3

"for every 60 moles of HNO3, you'll need _____ NO"

Try the other two in the same way.