How high would a 53 kg person running 7 m/s swing if they were on Mars ( g= 3.7 m/s^2)

Question

Please help. And in the explanation I would like to see the formula used to solve and what everything stands for thanks.

Answer 1

Sounds like this person catches a rope and swings upward. This is an energy transfer problem converting KE (1/2mv²) into PE (mgh) where m is the mass, v= velocity and h= height. Note that 1/2mv2=mgh since all of the KE is converted into PE. Since the m cancels, h=v²/2g = 49/2/3.7= 6.62 meters