Zn3N2 + 3 Cl2 → 3 ZnCl2 + N2
(3 mol Cl2/1 mol Zn3N2) (1 mol Zn3N2/224.2 g Zn3N2) 14.7 g Zn3N2 = 0.197 mol Cl2
Samantha A.
asked 01/26/21I am completely lost.
Zn3N2 + 3 Cl2 → 3 ZnCl2 + N2
(3 mol Cl2/1 mol Zn3N2) (1 mol Zn3N2/224.2 g Zn3N2) 14.7 g Zn3N2 = 0.197 mol Cl2
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