
Ashley P. answered 01/26/21
Effective and Patient Math, Science and English Tutor
Hi Shaylyn! here is how this problem would be set up:
5.00g N2 x (1 mol N2 / 28.00g N2) x (2 mol NaN3 / 3 mol N2) x (64.99g NaN3 / 1 mol NaN3) = 7.74g NaN3
When you solve this and cancel out like units, you should get 7.74g NaN3 are required. Hope this helps! Fell free to reach out with additional questions.