four times the sum of three consecutive odd integers is the same as 222 more than 6 times the largest integer. find the integers.

Answer 1

1st odd integer is X

2nd odd integer is X+2

3rd off integer is X+4

4 [ X + X+2 + X+4 ] = 222 + 6(x+4)

4 [ 3x+6] = 222 + 6x + 24

12x + 24 = 246 + 6x

6x + 24 = 246

6x = 222

x = 37

37, 39, 41

the total is 117

4*117 = 468

468-222 = 246

246/6 = 41 which is the largest,

so yes it checks

37,39, and 41 is the official answer