Derek S. answered 01/25/21
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A. If there is 10 ft of space after every float, and not just between them, then the total length is 40 ft per large float, and 25 ft per small float. Using this, you can write an equation for the total length.
B. Using the equation from part A, evaluate 150 ≤ L < 200. I would suggest for you to try checking the maximum number of both floats by imagining that only one size category existed, and fit it within 200 feet. Then slowly figure out the possible cases, remembering to be careful of the length constraints. L = 150 is fine, but L = 200 is not as the question says "less than" 200 ft and not "less than or equal to."
C. For this part, take your list of possible combinations from part B and just calculate the total costs for each. No need to redo previous work here. If the cost for one goes above $2500, then it is an invalid combination. From the surviving combinations, you can then more specifically tell what total lengths are possible, although the answer to part A remains the same.
Derek S.
Limiting the combinations by price further restricts the combinations from part B, but the original condition still applies. So it just shortens the list of answers a bit.01/25/21
Victor B.
Hi! I meant the Question in Letter C to be "How does this change your answers to part B?" instead of PArt A. Still a bit curious though. Thanks!01/25/21