
David C. answered 01/24/21
Enthusiastic, patient, and effective tutor.
For these types of questions you need to look at the balanced reaction:
2 N2O --> 2 N2 + O2
Now, we can divide everything by 2 in order to set the N2O coefficient to be 1:
N2O -->. N2 = 1/2 O2
From this equation we can see that for every mole of N2O consumed there is 1/2 mole of O2 produced.
Therefore, the average formation rate for O2 with be 1/2 times the consumption rate of N2O
Average Rate of Formation for O2 = 1/2 * 1.70x1--3 M s-1
Please leave a comment or a thumbs up if this was helpful or if you need further explanation.

David C.
The average rate of formation for O2 would be 1/2 times the average rate of consumption of N2O because each mole of N2O produces 1/2 mole of O2. So, the average rate of production for O2 over the same time period would be 1/2 * 1.70x10^-3 = 0.00085 M/s Does that help?01/24/21
Sanah H.
Got It thanks01/24/21

David C.
Your welcome. Hope this helps with similar problems.01/24/21
Sanah H.
So I am not sure what to multiply could you clarify.01/24/21