Hello, Molly,
We need to have a balanced equation of the reaction to answer this question. It would be helpful to have one already worked out, unless that is part of the reason you asked the question.
C3Hg, I suspect, was meant to be C3H8, Hg is mercury, a favorite element of mine, and it has more pride than to be caught with three carbons hanging on. :)
My try at a balanced reaction: 1C3H8 + 5O2 = 3CO2 + 4H2O
This tells us we'll get 4 moles of water for every mole of propane. Use this molar ratio (4 moles H2O/1 mole C3H8) to find the moles water theoretically produced.
(4 moles H2O/1 mole C3H8)*(2.08 moles C3H8) = 8.32 moles H2O
This is how many moles of water we should expect, assuming excess O2 and good lab technique.
Bob