y= a(x+8)(x-5)
10 =-40a
a = -1/4
y= (-1/4)(x^2 +3x -40
y = -x^2/4 -3x/4 +10
Tajae B.
asked • 01/22/21The parabola whose x-intercept
The parabola whose x-intercepts are -8 and 5 whose y-intercept is 10 has an equation of the form
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