need help w chemistry

Question

If 10.8 moles of sodium nitrate react with excess iron(III) chloride, how many moles of Iron(III) nitrate can theoretically be made?

Answer 1

The key to this problem is getting a balanced equation and determining the mole ratios involved.

NaNO₃ + FeCl₃ --> NaCl + Fe(NO₃)₃

3NaNO₃ + FeCl₃ --> 3NaCl + Fe(NO₃)₃ (balance chlorine then sodium and check other elements balance)

From the equation, you can see that one mole of iron(III) nitrate is formed from 3 moles of sodium nitrate

Thus 1.08 moles of sodium nitrate will produce 10.8/3 = 3.6 moles of iron(III) nitrate