Hello, Molly,
We need to have a balanced equation to start. This was a little more difficult than some, but here's where I wound up:
2Al2S3 + 3F2 = 2AlF3 + 6S
Check my work before going any further.
If this is correct and balanced, we want to find the number of moles of F2 that are consumed (F is a diatomic molecule), The balanced equations tells us that the molar ration of F2 to Al2S3 is 3/2. That is, 3 moles of F2 are required for every 2 moles of Al2S3.
Since we use 0.1031 moles of Al2S3, we'll consume 2*(0.1031) moles of F2. Assuming there is enough, we'd consume 0.2062 moles of F2.
I hope this helps,
Bob