need help with chemistry

Question

If 10.8 moles of sodium nitrate react with excess iron(lll) chloride, how many moles of iron(lll) nitrate can theoretically be made?

Answer 1

Hi Molly,

First let us set up the appropriate balanced equation for this problem:

3 NaNO₃ + FeCl₃ --> Fe(NO₃)₃ + 3 NaCl

Now we can use some basic dimensional analysis to figure out the number of moles of Iron (III) nitrate that can be theoretically made:

10 mol NaNO₃ x (1 mol Fe(NO₃)₃ / 3 mol NaNO₃) = 3.33 moles Fe(NO₃)₃