John B. answered 01/21/21
Patient and Knowledgeable Chemistry Tutor
16.49 g butanoic acid x 1mole/88 g butanoic acid x 1 mole ethyl butyrate/1mole butanoic acid x 126 g ethyl butyrate/1 mole ethyl butyrate = 23.57 g of ethyl butyrate
This is the theoretical yield
% yield = (actual yield/theoretical yield) x 100
95 = (actual/23.57) x 100
actual = 22.39 g