Unit 5 Quiz Review

Question

Find the percent of barium in barium phosphate (all numbers are to have 2 decimal places).

_____g  / ______g   x  _______%  = _______%

Please answer and explain.

Answer 1

Barium=Ba²⁺

Phosphate=PO₄^-3

Barium phosphate=Ba₃(PO₄)₂ so that the +6 and -6 charge cancel each other out

Molar mass=3Ba+2P+8O

3(137.33)+2(30.97)+8(16.00)=601.93g/mol

%Ba=(mass 3Ba/mass Ba₃(PO₄)₂)100

%Ba=(3[137.33]/601.93)100

%Ba=68.45

%P=(mass 2P/mass Ba₃(PO₄)₂)100

%P=(2[30.97]/601.93)100

%P=10.29%

%Ba+%P+%O=100%

68.45+10.29+x=100

x=21.26% O