Hello, Isabell,
The balanced equation tells us that two moles of CO will react with one mole of O2. If we find the number of moles in 784g of CO, we can take 1/2 of that to find the moles of O2 that are required. Find the molar masses (g/mole) of both CO and O2 and set up a table to keep things clear.
The molar mass of CO is 28g/mole. Moles of CO is found by dividing the actual mass by the molar mass. That comes out to a surprisingly eerie 28 moles. But that's what it is, and it makes me suspect that we're on the right track, after checking my division.
If we have 28 moles of CO, we then know we need half that of O2 to completely react, or 14 moles. To convert that to grams O2, multiply by oxygen's molar mass of 32g/mole. That result is 448 grams O2.
( Moles CO/Moles O2) = 2, as per the balanced equation.
Bob