what is the pH of a solution that contains 22 moles of nitric acid (HNO3) dissolved in 5000 L of water?

Answer 1

Step 1: Find the molarity

We have 22 moles of HNO3 in 5000L Water. Hence, 22 mol/ 5000L = 0.0044 M

Step 2: Dissociation of H+ ions

Since HNO3 is a strong acid, it completely dissociates. hence, we have 0.0044 M of H+ ions from 0.0044M solution

Step 3: pH

pH = -log[H+] = -log[0.0044] = 2.36.