How many grams of aluminum will be needed

Question

How many grams of aluminum will be needed to react to 50g of iron (III) oxide needs to fully react wit the equation FE2O3 + 2AI(S) = AI2O3(S) + 2 Fe (S)

Answer 1

Fe2O3 + 2AI(S) = AI2O3(S) + 2 Fe (S)

Convert 50g Fe2O3 to moles with molar mass

50g(1mol/159.69g)=0.31311mol Fe2O3

convert mole Fe2O3 to mol Al with coefficients:

0.31311molFe2O3(2molAl/1molFe2O3)=0.62621 mol Al

Convert to grams Al with molar mass:

0.62621 mol Al(26.98g/1mol)=16.895g Al

=16.9 g Al