Corban E. answered 01/19/21
AP Chemistry Tutor and Former Teacher (Gen Chem, IB, O-Level, A-Level)
6 Li + N2 = 2 Li3N
Use molar mass:
25g N2 (1molN2/28.02gN2)=0.89222mol N2
Use coefficients:
0.89222mol N2 (2mol Li3N/1mol N2)=1.7844 mol Li3N
use molar mass:
1.7844 mol Li3N (34.83gLi3N/1molLi3N)=6.2152 g Li3N