complete the following table summarizing the amounts of nitrogen and oxygen produced upon the decomposition of the sample of dinitrogen monoxide.

Question

Use the law of constant composition

                 Mass N2O   Mass N        Mass O
Sample A     2.85 g        1.82 g         1.03 g
Sample C    _____      _____           1.55 g



Use the law of constant composition to complete the following table summarizing the amounts of nitrogen and oxygen produced upon the decomposition of the sample of dinitrogen monoxide.


               Mass N2O     Mass N       Mass O
Sample A   2.85 g       1.82 g           1.03 g
Sample D  _____         2.11 g          _____

Answer 1

The law of constant composition states that a chemical compound always contains the same elements in the same proportion by mass, regardless of the amount of the compound.

1. From Sample A, we know:
2. Mass of N2O = 2.85 g
3. Mass of N = 1.82 g
4. Mass of O = 1.03 g
5. The ratios are:
6. Nitrogen ratio: 1.82/2.85 = 0.638
7. Oxygen ratio: 1.03/2.85 = 0.361
8. Sample C:
9. Mass of O = 1.55 g.
10. Using the oxygen ratio 0.361, we calculate:
11. Mass of N2O = 1.55/0.361 = 4.29g
12. Then, using the nitrogen ratio 0.638, we calculate:
13. Mass of N = 0.638 * 4.29 = 2.74g
14. Sample D:
15. Mass of N = 2.11 g.
16. Using the nitrogen ratio 0.638, we calculate:
17. Mass of N2O = 2.11/0.638 = 3.31g
18. Then, using the oxygen ratio 0.361, we calculate:
19. Mass of O = 0.361 * 3.31 = 1.20g

Final Results:

Sample C:

1. Mass of N2O = 4.29 g
2. Mass of N = 2.74 g
3. Mass of O = 1.55 g

Sample D:

1. Mass of N2O = 3.31 g
2. Mass of N = 2.11 g
3. Mass of O = 1.20 g

This method ensures the same ratios are applied to all samples, based on the law of constant composition.