I need help with the following derivative question.

Question

Let f(x) = x^2 + 3x and let g(x) and its derivative g prime (x) have the values shown in the table above. If h(x) = f(g(x)) , what is h prime (2)

x 1 2 3 4 5 6

g(x). 0 1 3 7 2 5

g’(x) 4 3 1 -1 -2 -1

Answer 1

By the chain rule h'(x) = f'(g(x)) g'(x)

So h'(2) = f'(g(2)) g'(2) = f'(1) g'(2)

f'(x) = 2x + 3 so f'(1) = 2 + 3 = 5

h'(2) = 5 x 3 = 15