Molecular Formula Practice

Question

Consider:

Acetylene, a gas used in welding torches, has the empirical formula of CH and a molar mass of 26.04 g/mol. 

The ratio for this problem is (two decimal places): 

	g/mol
	g/mol

The molecular multiplier integer is _______

The molecular formula is __________

Answer 1

Empirical Formula mass = 12.011 (C) + 1.0078 (H) = 13.02 g/mol

Molar mass = 26.04 g/mol

The molecular multiplier integer 'n' = Molar mass / Empirical formula mass

= 26.04 / 13.02

= 2

The molecular formula = (empirical formula)_n

= (CH)₂

= C₂H₂