Jon P. answered 02/24/15
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From sample A, you can see that the mass of resulting N is 1.82 / 2.85 = .639 = 63.9% of the mass of the initial N2O. And the mass of the resulting O is 36.1%.
The same percentages have to hold no matter what the input amount is.
So the mass of N in sample B is 63.9% of 3.15 = 2.01 g.
And the mass of O in sample B is 36.1% of 3.15 = 1.14 g.