Molecular Formula Notes Check

Question

Consider:

Acetylene, a gas used in welding torches, has the empirical formula of CH and a molar mass of 26.04 g/mol. 

The ratio for this problem is (two decimal places): 

	g/mol
	g/mol

The molecular multiplier integer is 

The molecular formula is 

Answer 1

The M_MF = nM_EF even though the empirical formula may not be a real substance. n is the multiplier.

n = M_MF/M_EF or molecular formula mass/ empirical formula mass

The formula from EF = CH is MF = C_nH_n

Note if you had an EF of CH₂ , the MF would be C_nH_2n

Take care.