Corban E. answered 01/12/21
AP Chemistry Tutor and Former Teacher (Gen Chem, IB, O-Level, A-Level)
1
NaOH(aq)--> Na+(aq)+OH-(aq)
2
[NaOH]=[OH-]
0.010
pOH=-log[OH-]
pOH=-log(0.010)
pOH=2.0
pH+pOH=14
14-2.0=pH
pH=12.0
[H+]=10-pH
[H+]=10-12
3
base because pH is greater than 7
4
NaOH(aq)+NH4Cl(aq)-->NaCl(aq)+NH4OH(aq)
net ionic
NH4+(aq)+OH-(aq)-->NH4OH(aq)