Ideal gas law combined gas law

Question

How many mols of chlorine gas are in a box if the box is 29.0 L in size, at 1.8 atm of pressure and at a temperature of 300K?

1. 
   

Answer 1

The underlying formula that you want to use to solve this one is

PV = nRT

In this scenario we're solving for the number of moles (n)

n = PV / RT

Plugging in the values that becomes

n = (1.8 atm * 29 L) / (0.0821 L*atm/mol*K * 300K)

n = 52.2/24.63 = 2.12 moles

meaning that there are approximately 2.12 moles of chlorine gas in the box

Answer 2

Hi Pia,

This is a fun plug-and-chug equation that uses the Combined gas Law Equation, PV=nRT

We just need to solve for the mols inside the container, represented by 'n'

Solved here:

PV=nRT

(1.8atm)(29.0L)= n(8.314)(300K)

n=0.021 mols