b2h6+3o2=b2o3+3h2o if you want 14.1 mol of water, how much borohydride will you need

Question

Im stuck with this question for my homework

Answer 1

Hello, Andres,

The correct name for B₂H₆ is diborane. We can answer this with the use of mole conversions. We want 14.1 moles of H₂O. The balanced equation says that we'll get three moles of water for every one mole of diborane. That means we need (1 moles B₂H₆ /3 moles H₂O )* (14.1 moles H₂O) = 4.7 moles B₂H₆. Determine the molar mass of B₂H₆ (27.6 g/mole) and multiply that times the moles of B₂H₆ needed to obtain the grams needed. I get 130 grams B₂H₆. Seems a shame to waste diborane just to make water, but perhaps OK on a space mission, if there is extra O₂ hanging around. But diborane is highly flammable, and will even react with water. I suggest assigning your interns to conduct the reaction.

Bob