Michael J. answered 02/24/15
Tutor
5
(5)
Applying SImple Math to Everyday Life Activities
Given:
m = 60 kg
PE = 1000 kg m2/s2
Part a)
Weight = mg
mg = (60 kg)(9.81 m/s2)
= 588.60 kg m/s2
Part b)
mgh = PE
h = PE / mg
h = (1000 kg m2/s2) / (588.60 kg m/s2)
h = 1.699 m
Part c
Conservation of energy states that PE + KE = 0
KE = -PE ----> negative sign in front of PE indicates loss of potential energy.
(1/2)mv2 = PE
mv2 = 2PE
v2 = (2PE/m)
v2 = (2* 1000 kg m2/s2) / 60 kg
v2 = 33.33 m2/s2
v =√(33.33 m2/s2)
v = 5.77 m/s