3 tan x + 3tan^2 x = 4 sec^2 x -2

Question

for 0<=x<=360 degrees

Answer 1

sec^2x = 1+ tan^2x

3tanx + 3tan^2x = 4(1+tan^2x) -2

tan^2x - 3tanx + 2=0

(tanx-1)(tan-2) = 0

tanx = 1,2

x = 45 degrees or 63.4 degrees or 225 degrees or 243.4 degrees, quadrants I and III