Raymond B. answered 01/06/21
Math, microeconomics or criminal justice
the arithmetic average is not less than the geometric average
1/1 > 1
(1+2)/2 > sqr(1x2)
3/2 > 1.414
1.5 > 1.414
(1+2+3)/3 > crt(1x2x3)
2 > cube root of 6
cube both sides to get
8 > 6
assume (1+2 + 3 + .... + n)/n > the nth root of n!
try to show (1+2 + 3 ...+n + n+1)/(n+1) > the n+1th root of (n+1)!
(1+2+...n)/n > nth root of n
add (n+1)/n to both sides
(1+2+...n+n+1)/n > (n!)^(1/n) + (n+1)/n
> (1^(1/n))(2^(1/n))....(n^(1/n)) + (n+1)/n
(n+1)/n is less than (3+1)/3 =1.333...for n greater than 2
show 4/3 < (n+1)^(1/n)
raise both sides to the n power
(4/3)^n < n+1
4/3 < 1+1
16/9 < 3
64/27< 4
assume (4/3)^n < n+1
try to show (4/3)^(n+1) < n+2