If 28 moles of Chlorine gas reacted with Aluminum, the product would be Aluminum Chloride. How many moles of Aluminum would be needed to make this reaction work?

Answer 1

Hello Izzy,

To figure out how many moles of Al is needed to make this reaction work, we need to create a balanced reaction. Aluminum Chloride is AlCl3, therefore our balanced reaction is as follows:

3Cl2(g) + 2Al(s) --> 2AlCl3(aq)

Based on the reaction, we now know that for every 3 moles of Cl2 gas, we need 2 moles of Aluminum to create 2 moles of AlCl3. If we have 28 moles of Cl2 then, for this reaction to work, we will need 18 moles of Al to create 18 moles of AlCl3. We will have 1 mole of Cl2 left over after this reaction.

I hope this helps!