Hello Sadie,
a) 40gCCl4 x (1mol CCl4 / 152g CCl4) x (4mol Cl / 1mol CCl4) x (6.022*10^23 atoms Cl / 1mol Cl) = 6.34*10^23 atoms of Cl
b) (5*10^23) atoms O2 x (1mol O2 / 6.022*10^23 atoms O2) x (1mol CO2 / 1mol O2)= 0.83 mol CO2
I hope this helps!


Rianna H.
tutor
Thank you for catching my mistake!
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12/31/20
J.R. S.
12/31/20