Rianna H. answered 12/30/20
Effective Science, Math and English Tutor
Hello Sadie,
a) 40gCCl4 x (1mol CCl4 / 152g CCl4) x (4mol Cl / 1mol CCl4) x (6.022*10^23 atoms Cl / 1mol Cl) = 6.34*10^23 atoms of Cl
b) (5*10^23) atoms O2 x (1mol O2 / 6.022*10^23 atoms O2) x (1mol CO2 / 1mol O2)= 0.83 mol CO2
I hope this helps!
Rianna H.
Thank you for catching my mistake!12/31/20
J.R. S.
12/31/20