Raymond B. answered 12/22/20
Tutor
5
(2)
Math, microeconomics or criminal justice
x^2(2x^2+5x-3) =
x^2(2x-1)(x+3).=
(x)(x)(2x-1)(x+3)
set each factor equal to zero to solve for zeroes
with zeroes -3, 0,0 and 1/2
4 zeroes, but one repeats