Raymond B. answered 12/22/20
Math, microeconomics or criminal justice
.1X + .3Y = .167(150)
X+Y = 150
X=150-Y
.1(150-Y) +.3Y = 25.05
.2Y = 25.05-15 = 10.05
Y = 50.25 of 30%
X= 150-50.25 = 99.75 of 10%
Victor B.
asked 12/20/20A candy distributor needs to mix a 10% fat-content chocolate with a 30% fat-content chocolate to create 150 kilograms of a 16.7% fat-content chocolate. How many kilograms of each kind of chocolate must they use?
Write an equation that uses the information as it is given above that can be used to solve this problem. Use x as your variable to represent the quantity of 10% fat-content chocolate.
Formula:_______________________
They must mix:
________________ Kilograms of the 10% chocolate and
________________Kilograms of the 30% chocolate.
Raymond B. answered 12/22/20
Math, microeconomics or criminal justice
.1X + .3Y = .167(150)
X+Y = 150
X=150-Y
.1(150-Y) +.3Y = 25.05
.2Y = 25.05-15 = 10.05
Y = 50.25 of 30%
X= 150-50.25 = 99.75 of 10%
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