25.0 mL of 0.212 M NaOH is neutralized by 13.6 mL of an HC1 solution. The molarity of the HC1 solution is?

Answer 1

The molarity of the HCl will be that which contains the number of moles of H+ in 13.6 mL equivalent to the number of moles of OH- in 25mL of 0.212M solution.

1. First, determine the number of moles of OH- in 25mL of a 0.212M solution. 0.212(0.025) = 0.0053 moles OH-.
2. Next, we determine the molarity of the HCl solution. If the solution has 0.0053 moles H+ in 13.6mL, then we can simple divide 0.0053 moles by 0.0136 L to get about 0.39M. Thus, the HCl solution should be about 0.39M.

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