Raymond B. answered 12/18/20
Math, microeconomics or criminal justice
2^5 = 32 subsets total, but subtract 1 to get the proper subsets = 31
proper means don't include the given set
5 subsets with just one element
10 with two elements
10 with three elements
5 with four elements
1 with five elements (don't count this one)
1 with no elements, the null set
32 subsets -1 = 31 proper subsets
You can also read off those numbers, 1,5,10,10,5,1 from Pascals triangle, 5th line for a 5 element set
Or, add up the combinations: 5C0 + 5C1 + 5C2 + 5C3 + 5C4 + 5C5 =1+5+10+10+5+1=32
5C0 = 5!/0!5! =1
5C1 = 5!/1!4! = 5
5C2 = 5!/2!3! =10
5C3 = 5!/3!2! =10
5C4 = 5!/4!1! = 5
5C5 = 5!/5!0! = 1