Raymond B. answered 12/26/20
Math, microeconomics or criminal justice
4 zeroes before the 9 is correct
5 is wrong
just a few observations about your answers, but I get into the zeroes towards the end:
.use the "rule of 9's"
add the digits
9+7+7= 23, 2+3= 5
5x5 =25 2+5=7
25x25 = 625 6+2+5 =13 1+3= 4
625x625 = 390625, a number that has 7 as the result
390625^2 results in 6
390625^4 results in 9
390625^8 results in 9
.977^400 results in 9
your answers is a long decimal that ends in 4
.977^400
is correct. = .00009....
.977^2 = .954529
.977^4 = .9542529^2 = .911125611
.977^8 = 0.83014988
.977^16 = 0.689148824
this calculator result seem to drop some decimals
...the last digit of your final calculation ends in a decimal digit 9
.977 to any power will go through a cycle of 7,9,3,1, then repeats
7^1 =7, 7^2 = 49 7^3 = 343, 7^4 = 2401. the last digit each time follows a repeating pattern, 7,9,3,1
7^8 ends in 1
7^16 ends in 1
7^400 ends in 1
Your calculation ends in 4, although best guess is it's truncated, leaving off other decimals
.977^128 = .050874968 = about 5 x 10^-2
.977^256= .002588262452 = about 2.59 x 10^-3
.977^384 = about 1.32 x 10^-4
.977^400 = .977^384(.977^16) = about 1.32 x 10^-4 x .69 = .908 x 10^-4
= 9.08 x 10^-5
you should have 9 x 10^-6 if you got 5 zeroes to the right of the decimal point,but 9x10^-5 and 4 zeroes is correct.
.01 = 1 x 10^-2 the absolute value of the exponent is 1 greater than the number of zeroes.